Question

calculati a) : [0,8+4x(0,34x10 \+1,2:2)]:0,168 b) 15x[6,4+2,2x(3, 1^{2} -4,61)]:2.

Answer 1

$a) [0,8+4*(0,34*10+1,2:2)]:0,168= \\ =[0,8+4*(3,4+0,6)]:0,168=[0,8+4*4]:0,168= \\ 16,8:0,168=100$
$b) 15*[6,4+2,2*((3,1)^2-4,61)]:2= \\ =15*[6,4+2,2*(9,61-4,61)]:2=15*[6,4+2,2*5]= \\ =15*[6,4+11]=15*17,4=261$