Question

Calculati a)1/2+2/3:4/9= b).1/12+4/5:(1/2-1/3)= c).2:(2/3)^2+11/5:11/10= .d).(1/4+7/6)•15/34+3/2•(1/3-1/21)= e).12,9+1,8•7= f).3+37:(1,8•7= g).(0,25)^7•(0,25)^14:(1/4)19+0,125 h).0,25•[1/3+1/4-0,1(6)]:2,5=
i).6+11/5:(2inntregi-2/3-1intreg1/5)+1:[(5/3+1/7-2/21)•1/6]=
j).[(3/5)^7:(2intregi-1intreg2/5)^4+5intregi:1intreg1/4-(3/5)^3]:1intreg3/5=
DAU COROANA

Answer 1

a)1/2+2/3:4/9=
=1/2 + 2/3 ×9/4=
=1/2 + 1×3totul supra/1×2=
=1/2 + 3/2=
=4/2 simplificat cu 2=
=2/1 =
=2

b).1/12+4/5:(1/2-1/3)=
=1/12+4/5 : 3×1-2×1 totul supra/6=
=1/12+4/5 :1/6=
=1/12 + 4/5 ×6/1=
=1/12 + 24/5=(dăm numitor comun pe 60)
=5×1+12×24 totul supra/60=
=293/60

c).2:(2/3)^2+11/5:11/10=
=2 : 2/3×2/3 + 11/5 ×10/11=
=2/1 : 2×2totul supra/3×3 + 1×2 totul supra/1×1=
=2/1 : 4/9 + 2/1=
=2/1 ×9/4 +2/1=
=1×9 totul supra/1×2 +2/1=
=9/2 +2/1 =
=9+2×2 totul supra/2=
=13/2

.d).(1/4+7/6)•15/34+3/2•(1/3-1/21)=
=3×1+2×7totul supra/12 ×15/34 +3/2 × 7×1-1totul supra/21=
=17/12 ×15/34 + 3/2 ×6/21 =
=1×5totul supra/4×2 + 1×3 totul supra/1×7=
=5/8 + 3/7= dăm n. c. 56
=7×5+8×3 totul supra/56=
=59/56

e).12,9+1,8•7=
=129/10 +18/10 ×7/1=
=129/10 + 18×7 totul supra/10×1=
=129/10 + 126/10= au acelasi n.c 10
=255/10=
=25,5

f).3+37:(1,8•7=
=3/1 + 37/1 :( 18/10 ×7/1)=
=3/1 + 37/1 : 18×7totul supra/10×1=
=3/1 +37/1 : 126/10=
=3/1 +37/1 ×10/126=
=3/1 +37×10totul supra/1×126=
=3/1 + 370/126=
=126×3+370totul supra/126=
=378+370totul supra/126=
=748/126 simplificat cu 2=
= 374/63=
= 5,(936507) ( daca ar fi necesar in zecimale rezultatul )

Sau :
3+37:(1,8•7)=
=3+37: 12,6=
=3+ 2, (936507)=
= 5, (936507)

g).(0,25)^7•(0,25)^14:(1/4)^19+0,125=
=(0,25)^7+14 :(1/4)^19 +0,125=
=(0,25)^21 : (0,25 am transformat 1/4)^19 + 0,125=
=(0,25)^21-19 +0,125=
=(0,25)^2 + 0,125=
=0,25×0,25 +0,125=
=0,0625 +0,125=
=0,1875

h).0,25•[1/3+1/4-0,1(6)]:2,5=
=0,25× (1/3 +1/4 -16-1totul supra/90):2,5=
=0,25×(1/3 +1/4 - 15/90) :2,5=
=0,25 ×( 60×1 +45×1-2×15)tot ăsta supra/180 :2,5= tu nu pune in paranteza doar tot supra ok?
=0,25× 75/180 :2,5=
=25/100 × 75/180 :25/10=
=25/100 ×75/180 ×10/25=
=25/100 × 3 ×1totul supra/18×1=
=25/100 ×3/18 =
=25×3 totul supra/100×18=
=75/180 =
=0,41 (6)

i).6+11/5:(2inntregi-2/3-1intreg1/5)+1:[(5/3+1/7-2/21)•1/6]=
= 6 +11/5 :(2×3+2totul supra/3 - 1×5+1totul supra/5) +1: [(7×5+3×1-2tot asta supra/21) ×1/6]=
=6 +11/5 :(8/3 -6/5)+1: (36/21 ×1/6)=
=6+ 11/5 : 5×8-6totul supra/15 +1 : 6×1 totul supra/21×1=
=6/1 +11/5 : 34/15 + 1/1 : 6/21 =
=6/1 +11/5 ×15/34 +1/1 ×21/6=
=6/1 + 11×3totul supra/1×34 + 21/6=
=6/1 + 33/34 +21/6=
= 102×6+3×33+17×21 tot asta supra /102=
=1068/102 simplificat cu 2=
=534/51

j).[(3/5)^7:(2intregi-1intreg2/5)^4+5intregi:1intreg1/4-(3/5)^3]:1intreg3/5=

=[(3/5)^7 :( 2 - 1×5+2totul supra/5)^4 +5 : 1×4+1totul supra/4 -(3/5)^3]: 1×5+3totul supra/5=
=[ (3/5)^7 : (2 - 7/5)^4+5 : 5/4 -(3/5)^3]: 8/5=
=[(3/5)^7 :( 5×2-7totul supra/5)^4 + 5/1 ×4/5 - (3/5)^3] × 5/8=
=[(3/5)^7 :(3/5)^4 +4/1 -(3/5)^3] ×5/8=
=[(3/5)^(7-4) astea sunt puterile +4/1 -(3/5)^3 ]×5/8=
=[(3/5)^3 + 4/1 -(3/5)^3]×5/8=
=[(3/5)^3-3 +4/1]×5/8=
=[(3/5)^0 +4/1]×5/8=
=(1 /1 +4/1)×5/8=
= 5/1 ×5/8 =
=5×5totul supra/1×8=
=25/8