Question

Calculați:
à) {1 + [25 – 3. (12x4-43)]x5}x4. b)6x{[75-5x13)x5-43]x7+1}. Dau coroana.va rog repedeee

Answer 1

Răspuns:

a)

{1 + [25 – 3x(12x4-43)]x5}x4

{1+[25-3x(48-43)]X5}X4

[1+(25-3x5)X5]X4

[1+(25-15)X5]X4

(1+10x5)X4

(1+50)X4

51x4=204

b)

6x{[75-5x13)x5-43]x7+1}=

6x{[75-65)x5-43]x7+1}=

6x[(10x5-43)x7+1]=

6x[(50-43)x7+1]=

6x(7x7+1)=

6x(49+1)=

6x50=300

Answer 2

Răspuns:

a)

{1 + [25 - 3 × (12 × 4 - 43)] × 5} × 4 =  

{1 + [25 - 3 × (48 - 43)] × 5} × 4 =  

[1 + (25 - 3 × 5) × 5] × 4 =  

[1 + (25 - 15) × 5] × 4 =  

(1 + 10 × 5) × 4 =  

(1 + 50) × 4 =  

51 × 4 =  

204

                               

b)

6 × {[75 - 5 × 13) × 5 - 43] × 7 + 1} =  

6 × {[75 - 65) × 5  - 43] × 7 + 1} =  

6 × [(10 × 5 - 43) × 7 + 1] =  

6 × [(50  - 43) × 7 + 1] =  

6 × (7 × 7 + 1) =  

6 × (49 + 1) =  

6 × 50 =

300