Question

Calculati:
a)1 intreg 5/7*(1/3+0,25)
b)1,25:5/4-3,(3)*0,3+0,1(6)
c) [0,1(26):25/198+2]:0,2
d) [4/3-0,(3)] la puterea 2:0,25
e) (1/2) la puterea 2 *[3,331-(1+0,1)] la puterea 2
f) (0,5) la 2/0,(6)+1+22/27-0,375
g)1/2+11/22+111/222

Answer 1

a) 12/7 × (1/3 + 1/4) = 12/7 × 7/12 = 1
b) 5/4 × 4/5 - 3 intregi 1/3 × 3/10 + 1/6 =
1 - 1 + 1/6 = 1/6 = 0,1(6)
c) (25/198 × 198/25 +2) × 5 = 15
d) (4/3 - 1/3)^2 × 4 = 1×4 = 4
e) 1/4 × (3,331-1,1)^2 = 1/4 × 4,977361 = 1, 24434025
Personal, cred ca ai gresit ceva in redactarea acestui subpunct...
f) 1/4 : 2/3 + 1 + 22/27 - 3/8 = 1/4 × 3/2 + 1 + 22/27 - 3/8 = 3/8 + 1 + 22/27 - 3/8 = 49/27 = 1 intreg 22/27
g) Numitor comun :
2=1×2
22=2×11
222=2×3×37
c.m.m.m.c.=2×3×11×37=2442
(1×1221+11×111+111×11) = (1221+1221+1221)/2442 = 3663/2442 = 3/2 = 1 intreg 1/2