Question

Calculati :
a) 1 supra 3 x 6 + 4 supra 3 x 21 supra 28 + 3 integ 1 supra 2 x 7 intreg 3 supra 5 =
b) (65 supra 195 + 108 supra 324 + 122 supra 366) x ( 24 supra 168 - 6 supra 42 ) =
c) ( 3 intreg 1 supra 4 + 1 intreg 2 supra 7 - 1 intreg 17 supra 28 ) x 1 intreg 15 supra 41 =
d) 270 supra 63 x (3 intreg 1 supra 5 + 7 intreg 1 supra 15 - 2 intreg 1 supra 3 ) =

Answer 1

a) 1/3*6+4/3*21/28+7/2*38/5=
2+1+133/5=
aducem la acelasi numitor 5
10+5+133/5=148/5
b) (65/195+108/324+122/366)*(24/168-6/42)=
(1284660+1284660+1284660/3853980)*(24-24/168)=
1*0=0
c) (13/4+9/7-45/28)*56/41=
(91+36-45/28)*56/41=
82/28*56/41=4
d) 270/63*(16/5+106/15-7/3)=
270/63*(48+106-35/15)=
270/63*119/15=