Question

Calculati:
a)[1 supra 4+(5 supra 2 - 1 intreg si 3 supra 4) : 7 supra 8] × 14;
b)[(1 supra 12 + 1 supra 10 + 4 supra 15 ) : 1 supra 15 +2 : 1 supra 18] × 4 supra 11;

Answer 1

a)
[ 1/4 + (5/2 - 7/4 : 7/8] × 14 =

= [ 1/4 + 5/2 - 7/4 ×8/7] ×14 =

= (1/4 + 5/2 - 2) × 14 =

= (1/4 + 10/4 - 8/4) × 14 =

= 3/4 × 14 =

= 42/4 =

= 10,5

b) [(1/12 + 1/ 10 + 4/15 ) :1/15 +2 : 1/18] × 4/11
= [(5/60 + 6/60 + 16/60)×15 + 2×18] ×4/11 =

= (27/60 × 15 + 36) × 4/11 =

= (27/4 + 36) × 4/11 =

= (27 +4×36)/4 × 4/11 =

= 171/4 × 4/11 =

= 171 / 11