Question

Calculați : a) (1 supra 7 +7 supra 11 - 2010 supra 2011) + ( 6 supra 7 + 4 supra 11 - 2010 supra 2011 b) (5 supra 3 + 7 supra 5 + 9 supra 7) - (2 supra 3 + 2 supra 5 + 2 supra 7

Answer 1

ai rezolvarea în imagine

Answer 2

a) $( \frac{1}{7}+ \frac{7}{11}- \frac{2010}{2011})+( \frac{6}{7}+ \frac{4}{11}- \frac{2010}{2011})=(- \frac{34110}{154847})+ \frac{34264}{154847}$$=\frac{34110}{154847}+ \frac{34264}{154847} = \frac{-34110+34264}{154847}= \frac{154}{154847}= \frac{2}{2011}$ ≈ 0.00099453

b) $( \frac{5}{3}+ \frac{7}{5}+ \frac{9}{7})-( \frac{2}{3}+ \frac{2}{5}+ \frac{2}{7})= \frac{457}{105}- \frac{142}{105}= \frac{457-142}{105}= \frac{315}{105}=3$