Question

calculati:a)10•{18^2:324+2•[(2^2•3)^15:(2^29•3^15)+1^24]}=,b)3^100:[3^40•3^58+(3^10•3^15)^5:3^27+(4^57:4^56-1^4)^90•3^8].

Answer 1

a)10•{18^2:324+2•[(2^2•3)^15:(2^29•3^15)+1^24]}=
=10•{18^2:18^2+2•[(2^30•3^15):(2^29•3^15)+1]}=
=10•[1+2•(2+1)]=
=10•(1+6)=
=70

b)3^100:[3^40•3^58+(3^10•3^15)^5:3^27+(4^57:4^56-1^4)^90•3^8]=
=3^100:[3^98+(3^25)^5:3^27+(4-1)^90•3^8]=
=3^100:(3^98+3^125:3^27+3^90•3^8)=
=3^100:(3^98+3^98+3^98)=
=3^100:3^98×(1+1+1)=
=3^100:3^98×3=
=3^100:3^99=
=3