Question

Calculati:
a) (11 pe 6+ 3 pe 4):31 pe 24
b) (5 pe 6+ 11 pe 9):74pe 9
c) (1pe 6+ 17 pe 8):77pe 24+2pe 7
d) (11pe 12-13pe 18):7
e) 19pe45-7pe 30):34 pe 5
f) (13 pe 12-7 pe 15):37pe 30+1pe2
Va roogggg!!!! Dau coronita

Answer 1

$a)(\frac{11}{6}+ \frac{3}{4}) : \frac{31}{24}= \\ \\ (\frac{11*2}{12}+ \frac{3*3}{12}) : \frac{31}{24}= \\ \\ (\frac{22}{12}+ \frac{9}{12}) : \frac{31}{24}= \\ \\ \frac{31}{12} : \frac{31}{24}=\\ \\ \frac{31}{12} *\frac{24}{31}=2$

$b) (\frac{5}{6} + \frac{11}{9}): \frac{74}{9} = \\ \\ \frac{5*9}{54}+ \frac{11*6}{54}: \frac{74}{9} = \\ \\ \frac{45+66}{54}* \frac{9}{74} = \\ \\ \frac{111*9}{54*74} = \frac{111}{444}= \frac{1}{4}$

$c)( \frac{1}{6}+ \frac{11}{8} ): \frac{17}{24}+ \frac{2}{7}= \\ \\ =\frac{8+66}{48} * \frac{24}{17}+ \frac{2}{7} \\ \\ = \frac{74}{48}* \frac{24}{17}+ \frac{2}{7} = \frac{74}{2}* \frac{1}{17} + \frac{2}{7} = \frac{74}{34} + \frac{2}{7} = \frac{327}{238}$

$d)( \frac{11}{12}- \frac{13}{18}):7= \\ \\ \frac{11*18-13*12}{12*18}:7= \frac{198-156}{216} :7= \\ \\ = \frac{42}{216}* \frac{1}{7} = \frac{1}{36}$

$e)( \frac{19}{45}- \frac{7}{30}): \frac{34}{5} = \\ \\ ( \frac{19*2-7*3}{90})* \frac{5}{34} = \\ \\ \frac{38-21}{90}* \frac{5}{34}= \frac{17}{90}* \frac{5}{34}= \frac{1}{36}$

$f)( \frac{13}{12} - \frac{7}{15}: \frac{37}{30}+ \frac{1}{2}= \\ \\ \frac{13*15-7*12}{12*15})* \frac{30}{37}+ \frac{1}{2} = \\ \\ \frac{195-84}{180} * \frac{30}{37}+ \frac{1}{2}= \\ \\ \frac{111}{180}* \frac{30}{37}+ \frac{1}{2}= \\ \\ \frac{111}{222}+ \frac{1}{2}= \frac{1}{2}+ \frac{1}{2}= \frac{2}{2} =1$