Question

Calculati:a){[1200×(8-200÷25)+36]-3096÷387}÷2la2= ;b)13 la 2+5×{2316÷579+[40+2la3×(2la4×5la2÷10-2la2×3la2)]×5}+11= ;c)2×[3la3×2la4÷3÷(148÷37+12)]-882÷49=

Answer 1

a)  { [ 1 200 x ( 8 - 200 : 25 ) + 36 ] - 3 096 : 387 } : 2² = 7

= { [ 1 200 x ( 8 - 8 ) + 36 ] - 8 } : 4 =

= [ ( 1 200 x 0 + 36 ) - 8 ] : 4 =

= ( 36 - 8 ) : 4 =

= 28 : 4 =

= 7

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b)  

13² + 5 × { 2 316 : 579 + [ 40 + 2³ x ( 2⁴x 5² : 10 - 2² x 3² ) ] x 5 } + 11

= 169 + 5 x { 4 + [ 40 + 8 x ( 20² : 10 - 6² ) ] x 5 } + 11 =

= 169 + 5 x { 4 + [ 40 + 8 x ( 40 - 36 ) ] x 5 } + 11 =

= 169 + 5 x [ 4 + ( 40 + 8 x 4 ) x 5 ] + 11 =

= 169 + 5 x ( 4 + 72 x 5 ) + 11 =

= 169 + 5 x ( 4 + 360 ) + 11 =

= 169 + 5 x 364 + 11 =

= 169 + 1 820 + 11 =

= 2 000

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c)

2 x [ 3³ x 2⁴ : 3 : ( 148 : 37 + 12 ) ] - 882 : 49 = 0

= 2 x [ 9 x 16 : ( 4 + 12 ) ] - 18 =

= 2 x 9 - 18 =

= 18 - 18 =

= 0