Question

Calculati:
a)[123+2 la puterea 7*2 la puterea 2+2 la puterea 67:2 la puterea 27]:[123+2 la puterea 14:2 la puterea 5+(2 la puterea 5) totul la puterea 8]=
Va rog repede!!!!

Answer 1

(123+2 la puterea 9+2 la puterea 40 ): (123+2 la puterea 9 +2 la puterea 40)= 1

Answer 2

$[123+2^7 \cdot2^2+2^6^7:2^2^7]:[123+2^1^4:2^5+(2^5)^8]= \\ =(123+2^{7+2}+2^{67-27}):(123+2^{14-5}+2^4^0)= \\ =(123+2^9+2^4^0):(123+2^9+2^4^0)=1$