Question

Calculati:
a) 1intreg si 1supra2+4supra9×2 intregi si 1supra 4.
B) (7supra8×2intregi si 2supra3+3 intregi si 1supra3×2intregi si 1supra10)×6supra28
C)0,5+11supra 12:[0,4+1,3-1,(3). Coronita!

Answer 1

a).
$1 \frac{1}{2} +\frac{4}{9} * 2\frac{1}{4}= \frac{1*2+1}{2} + \frac{4}{9} * \frac{2*4+1}{4} = \frac{3}{2}+\frac{4}{9}*\frac{9}{4}= \frac{3}{2}+1$
A ramas 1, deoarece se simplifica 4 cu 4 de pe diagonala si analog pt 9.
Se amplifica 1 cu 2 si vom obtine: 
$=\frac{3+2}{2}=\frac{5}{2}$

b). 
$=(\frac{7}{8}*\frac{2*3+2}{3}+\frac{3*3+1}{3}*\frac{2*10+1}{10})*\frac{6}{28}=$
$= (\frac{7}{8}*\frac{8}{3}+\frac{10}{3}*\frac{21}{10})*\frac{6}{28}=$
$=(\frac{7}{3}+7)*\frac{6}{28}=$
$=\frac{7+21}{3}*\frac{6}{28}=\frac{28}{3}*\frac{6}{28}=2$