Question

Calculati:
a: (1supra2+1,2):0,34
b: (3dupra4+2,65):0,25
c: (5supra8-0,12):1,01
va rog este urgent
dau coroana și multe puncte​

Answer 1

Răspuns:

Explicație pas cu pas:

$\\a,b=\frac{ab}{10}......a,bc=\frac{abc}{100} \\ \\ \\ \displaystyle(\frac{1}{2} +1,2):0,34=(0,5+1,2):0,34=1,7:0,34=5\\\displaystyle(\frac{1}{2} +1,2):0,34=(^{(5}\frac{1}{2} +\frac{12}{10} ):\frac{34}{100} =(\frac{5}{10} +\frac{12}{10} ):\frac{34}{100} =\frac{17}{10} :\frac{34}{100} =\frac{17}{\not10} \times \frac{\not100}{34} =\frac{\not17\times 10}{\not34} =\frac{10}{2} =10:2=5$

$\displaystyle (\frac{3}{4} +2,65):0,25=(0,75+2,65):0,25=3,5:0,25=13,6\\\displaystyle (\frac{3}{4} +2,65):0,25=(^{(25}\frac{3}{4} +\frac{265}{100} ):\frac{25}{100}^{(25} =(\frac{75}{100} +\frac{265}{100}): \frac{1}{4} =\frac{340}{100} :\frac{1}{4} =\frac{340}{100} \times 4^{(4}=\frac{340}{25} ^{(5}=\frac{68}{5}=13,6$

$\displaystyle (\frac{5}{8} -0,12):1,01=(0,625-0,12):1,01=0,505:1,01=0,5\\\displaystyle (\frac{5}{8} -0,12):1,01=(\frac{5}{8} -\frac{12}{100} ^{(4}):\frac{101}{100} =(^{(25}\frac{5}{8} -^{(8}\frac{3}{25} ):\frac{101}{100} =(\frac{125}{200} -\frac{24}{200})\times\frac{100}{101} =\frac{\not101}{200} \times\frac{100}{\not101} =\frac{100}{200}^{(10} =\frac{1}{2}=0,5$