Question

calculati a^2-1 unde a= [(7/3-11/6-5/2):0,(6)+0,2]:0.05

Answer 1

0,(6)=6/9=2/3
0,2=2/10=1/5
0,05=5/100=1/20
amplificãm pe 7/3 cu 6,pe 11/6 cu 3 si pe 5/2 cu 9
a=[(42/18-33/18-45/18):2/3+1/5]:1/20
a=[-36/18×3/2+1/5]:1/20
a=[-18/6+1/5]:1/20
a=[-3+1/5]:1/20 amplificãm pe -3 cu 5
a=[-15/5+1/5]:1/20
a= -14/5×20
a= -56
a^2-1= (-56)^2-1 =3136-1=3135