Question

calculati:
a) 2(√2+3)^2-4√2(3-√2)
b)3(√3-1)^2-√3(√3-6)-(√11-√2)(√11+√2)

Answer 1

a) 2(√2+3)²-4√2(3-√2)=
=2(2+6√2+9)-12√2+8=
=2(11+6√2)-12√2+8=
=22+12√2-12√2+8=
=30

b)3(√3-1)²-√3(√3-6)-(√11-√2)(√11+√2)=
=3(3-2√3+1)-3+6√3-11+2=
=12-6√3-3+6√3-9=
=12-12=0