Question

Calculati: a= 2√24(3_√6-√2_√3) b= 2√2·[2√243+2(4√32-3√27)] c=(8_√3+7_√2)√6-√24(6_√2+4_√3 (Linia asta  _  este supra sa stiti care vor sa ma ajute va rog mult  :( 

Answer 1

a = 2√24 ( 3 / √6  - √2 / √3),  / =  supra
a = 2√2²·3 ( 3√6 / (√6)² - √6 /( √3)² ) , rationalizezi in paranteza
a = 4√6 ( 3√6 / 6 - √6 / 3)
a = 4√6 ( 3√6 /6 - 2√6 /6)
a = 4√6 · √6 / 6
a = 4 ( √6)² / 6
a = 4·6 / 6
a = 24/6
a = 4
b = 2√2([ 2√243 + 2( 4√32 - 3√27)]
b = 2√2· [( 2√3²·3²·3 + 2 ( 4√2²·2²·2 - 2√3³)]
b = 2√2 · [ ( 2·3·3√3 + 2 ( 4·2·2√2 - 2·3√3)[
b = 2√2 · [ 18√3 + 2( 16√2 - 6√3)]
b = 2√2 · ( 18√3 + 32√2 - 12√3)
b = 2√2 · ( 6√3 + 32√2)
b = 12√6 + 64·2
b = 12√6 + 128
c = ( 8 / √3 + 7 /√2)· √6 - √24 ( 6/ √2 +  4 /√3)
c = ( 8√3 / 3 + 7√2 /2)· √6 - √2²·3 ·( 6√2/2 + 4√3/3)
c = 8√18 / 3 + 7√12 /2 - 2√6·( 3√2 + 4√3 / 3)
c = 8√2·3² /3 + 7√2²·3 /2 -  6√12 - 8√18 / 3
c = 24√2 /3  +  14√3 /2  -  6√2²·3  -  8√2·3² /3
c = 8√2 + 7√3 - 12√3 - 24√2 /3
c = 8√2 + 7√3 - 12√3 - 8√2
c = - 5√3