Question

Calculati: a. [(2^3)^2-2003^0]:3^2^1^2005-(1^3^4+2^2^1^2005)= b. 81˙x11^4-3^4x11^4+1=

Answer 1

[(2^3)^2-2003^0]:3^2^1^2005-(1^3^4+2^2^1^2005) =

( 8^2 - 1) : 3^2 - ( 1 + 2^2) =

( 64 - 1) : 9 - ( 1 + 4) =

63 : 9 - 5 =

7 - 5 =

2
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81 × 11^4 - 3^4 × 11^4 + 1 =

11^4 × ( 81 - 3^4) + 1 =

11^4 × ( 81 - 81) + 1 =

11^4 × 0 + 1 =

0 + 1 =

1
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