Question

Calculati:
a) (2-3radical din 2)^2

Answer 1

$(2- 3 \sqrt{2})^{2}$ =

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$(a-b)^{2} = a^{2} - 2ab + b^{2}$
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= $2^{2}$ - $2 * 3 *\sqrt{2}$ + ($3^{2} * \sqrt{2} ^{2}$)
= $4- 6 \sqrt{2} +18$ =
= $22- 6 \sqrt{2}$

Answer 2

$(2 - 3\sqrt{2} )^{2}$
$4 - 12 \sqrt{2} + 18$
$22 - 12 \sqrt{2}$
$folosesti \: formula \: (a - b)^{2} = {a}^{2} - 2ab + {b}^{2}$