Question

Calculati: a=2(8+ radical din 18) - 3(4+ radical din 8)

Answer 1

$a = 2(8 + \sqrt{18} ) - 3(4 + \sqrt{8} )$

$a = 2(8 + 3 \sqrt{2} ) - 3(4 + 2 \sqrt{2} )$

$a = 16 + 6 \sqrt{2} - 12 - 6 \sqrt{2}$

$a = 16 - 12 + 6 \sqrt{2} - 6 \sqrt{2}$

$a = 4$

Answer 2

A=2(8+√18)-3(4+√8)=
A=2(8+3√2)-3(4+2√2)
A=16+6√2−12−6√2
Α=16−12
A= 4