Question

Calculați : a) 2018^0 + 1^2020 + 2019^1-0^2020 b) 5×[3×3^2×3^2-2^32:2^28+(5^3)^3:5^8] ​

Answer 1

Explicație pas cu pas:

a) 2018^0+1^2020+2019^1-0^2020=

1+1+2019-0=

2+2019+=2021

b) 5×[3×3^2×3^2-2^32:2^28+(5^3)^3:5^8]=

5×(3×9×9-2^4+5^6:5^8)=

5×(27×9-32+5^2)=

5×(243-32+25)=

5×(211+25)=

5×236=1.180

Sper ca te-am ajutat! Succes!!