Matematică, întrebare adresată de sanzianastavarache11, 8 ani în urmă

Calculați:
a) 23+7x{41+4x[3+8x(11x12-8x10)-59]}+1002=
b) (29x14-29x4)+12x11+8x{125-5x[340-2x(22x19-23x11)]}=
c) 1+11x{1+11x[1+11x(11x11-120)]}+11x11=
d)[103-3x(21x11-23x9)]x{3+5x[2+3x(5+5x6)]}=​

Răspunsuri la întrebare

Răspuns de pippa0
3

Răspuns:

a)23+7×{41+4×[3+8×(11×12-8×10)-59]}+1002=

23+7×{41+4×[3+8×(132-80)-59]}+1002=

23+7×[41+4×(3+8×52-59)]+1002=

23+7×[41+4×(3+416-59)]+1002=

23+7×[41+4×(419-59)]+1002=

23+7×(41+4×360)+1002=

23+7×(41+1440)+1002=

23+7×1481+1002=

23+10367+1002=

10390+1002=11392

b)(29×14-29×4)+12×11+8×{125-5×[340-2×(22×19-23×11)]}=

(406-116)+132+8×{125-5×[340-2×(418-253)]}=

290+132+8×[125-5×(340-2×165)]=

290+132+8×[125-5×(340-330)]=

290+132+8×(125-5×10)=

290+132+8×(125-50)=

290+132+8×75=

290+132+600=

422+600=1022

c)1+11×{1+11×[1+11×(11×11-120)]}+11×11=

1+11×{1+11×[1+11×(121-120)]}+121=

1+11×[1+11×(1+11×1)]+121=

1+11×[1+11×(1+11)]+121=

1+11×(1+11×12)+121=

1+11×(1+132)+121=

1+11×133+121=

1+1463+121=

1464+121=1585

d)[103-3×(21×11-23×9)]×{3+5×[2+3×(5+5×6)]}=

[103-3×(231-207)]×{3+5×[2+3×(5+30)]}=

(103-3×24)×[3+5×(2+3×35)]=

(103-72)×[3+5×(2+105)]=

31×(3+5×107)=

31×(3+535)=

31×538=16678

sper că te-am ajutat!


sanzianastavarache11: MULȚUMESC!!!
pippa0: cu plăcere
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