Matematică, întrebare adresată de alinuzza, 9 ani în urmă

Calculati:a)25^4)^3):(4^2+3^2)^11)-(0^2010+1^2012+2013^0)
b)[123+2^7×2^2+2^67:2^27]:[123+2^14:2^5+(2^5+)^8];
c)(2^8+9^2+5^6+36^2):(0^6+4^4+3^4+25^3+6^4);
d)(4+8+12+16+....+8000):(2+4+6+8+...+4000)+(2^53+2^52+2^51):(2^17)^3;
e){637+15%×[15×(282:47+516:43):45-6]:21}:13=;
f)(6+12+18+24+...+600)^2:(3+6+9+12+...+300):(1+2+3+...+100)=.
DAU CORONITA!!!

Răspunsuri la întrebare

Răspuns de cocirmariadenis
67

a )

( 25⁴ )³ : ( 4² + 3² ) ¹¹ - ( 0²⁰¹⁰ + 1²⁰¹² + 2013⁰ ) = 23

= 25 ¹² : ( 16 + 9 )¹¹ - ( 0 + 1 + 1 ) =

= 25¹² : 25¹¹ - 2 =

= 25¹ - 2 =

= 23

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b)

[ 123 + 2⁷ x 2² + 2⁶⁷ : 2²⁷ ] : [ 123 + 2¹⁴ : 2⁵ + ( 2⁵ )⁸ ] = 1

= [ 123 + 2⁹ + 2 ⁴⁰ ] : [ 123 + 2⁹ + 2⁴⁰ ] =

= 1

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c)

( 2⁸ + 9² + 5⁶ + 36² ) : ( 0⁶ + 4⁴ + 3⁴ + 25³ + 6⁴ ) = 1

= ( 2⁸ + 3⁴ + 5⁶ + 6⁴ ) : ( 0 + 2⁸ + 3⁴ + 5⁶ + 6⁴ ) =

= 1

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d)

( 4 + 8 + 12 + 16 + ...+ 8000) : ( 2 + 4 + 6 + .....+ 4000 ) + ( 2⁵³ + 2⁵² + 2⁵¹ ):(2¹⁷)³=

= 2 ( 2 + 4 + 6 + ......+ 4000 ) : ( 2 +4 + 6 +......+ 4000 ) + 2⁵¹ ( 2² + 2 + 1 ) : 2⁵¹ =

= 2 x 1 + 1 x ( 4 + 3 ) =

= 2 + 7 =

= 9

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e)

{ 637 + 15%x [ 15 x ( 282 : 47 + 516 : 43 ) : 45 - 6 ] : 21 } : 13 = 49

= { 637 + 15 / 100 x [ 15 x ( 6 + 12 ) : 45 - 6 ] : 21 } : 13 =

= [ 637 + 3 / 20 x ( 15 x 18 : 45 - 6 ) : 21 ] : 13 =

= [ 637 + 3 / 20 x ( 270 : 45 - 6 ) : 21 ] : 13 =

= [ 637 + 3 / 20 x ( 6 - 6 ) : 21 ] : 13 =

= ( 637 + 3 / 20 x 0 : 21 ) : 13 =

= 637 : 13 =

= 49

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f)

( 6 + 12 + 18 + 24 + ......+ 600 )² : ( 3 + 6 + 9 + 12 + .......+ 300 ) : ( 1 + 2 + 3 + .....+ 100) = 12

= 2² ( 3 + 6+ 9 + 12 + ......+ 300)² : (3 + 6 + 9 + 12 + .....+ 300 ) : ( 1 + 2 + 3 + ...+100) =

= 2 ² ( 3 + 6 + 9 + ......+ 300 ) ⁽²⁻¹ : ( 1 + 2 + 3 + .......+ 100 ) =

= 4 x 3 ( 1 + 2 + 3 + ......+ 100 ) : ( 1 + 2 + 3 + ........+ 100 ) =

= 12 x 1 =

= 12



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