Question

Calculati

a) 27^3:[(-3)^4*3^5]*9^2 =
b) 5*{-14+2*[-7+7*(8-8:2)]} =
c) 3(2x-1)=4x+5 , in Q
d)480:[18-(6-x)]+4=10 , in Z

Dau coronita !

Answer 1

a) =(3³)³:(-3)⁹*(3²)²=
=3⁹:(-3)⁹:3⁴=
=-1:3⁴=
=-1/81
b) =5*{-14+2*[-7+7*(8-4)]}=
=5*{-14+2*[-7+7*4]}=
=5*{-14+2*[-7+28]}=
=5*{-14+2*21}=
=5*{-14+42}=
=5*28=
=140
c) 6x-3=4x+5
6x-4x=3+5
2x=8
x=8/2
x=4
d) 480:[18-6+x]=10-4
480:[18-6+x]=6
18-6+x=480:6
12+x=80
x=80-12
x=68