Question

Calculati :
a)2radical din 2 * (-3rad.din 2 ) +15=
b)6 rad.din 12 : (2 rad.din 3 ) - 7 =
c)rad.din 3 * (rad.din 3 +3 )-3 rad.din 3=
d)(rad.din 98 - rad.din 50) : (-rad.din 2 )=
Va rog frumos , cu tot cu rezolvare . Nu de asta , dar nu vreau doar raspunsul , ca il am si la sfarsitul cartii....Dau coroana..

Answer 1

   
[tex]a)~~2 \sqrt{2} \times (-3) \sqrt{2} + 15 = \\ = -2 \times 3 \times \sqrt{2} \times \sqrt{2} + 15 = -6 \times 2+ 15 = -12+15=\boxed{3} \\ \\ b)~~ \frac{6 \sqrt{12}}{2\sqrt{3}} - 7 = \frac{6 \sqrt{4 \times 3}}{2\sqrt{3}} - 7 = \frac{6 \times 2\sqrt{3}}{2\sqrt{3}} - 7 = 6 - 7 = \boxed{-1} [/tex]


$c)~~\frac{ \sqrt{98}-\sqrt{50} }{-\sqrt{2}} = \frac{ \sqrt{49 \times 2}-\sqrt{25 \times 2} }{-\sqrt{2}} = \frac{ 7\sqrt{2}-5\sqrt{2} }{-\sqrt{2}} = -\frac{ 2\sqrt{2}}{\sqrt{2}} = \boxed{-2}$