Question

calculati : a) 3⁰+0³+2³,b)
3⁵×3⁸:3¹¹,c)36:(2²×3)+72:(2×3²) , d ) (2¹⁸+4⁸):8⁵​

Answer 1

a) 3⁰+0³+2³ = 1+0+8 = 9

b) 3⁵×3⁸:3¹¹ = 3^(5+8-11) = 3² = 9

c)36:(2²×3)+72:(2×3²) = 36:(4·3) + 72:(2·9) = 36:12 + 72:18 = 3+4 = 7

d) (2¹⁸+4⁸):8⁵​ = ((2¹⁸+(2²)⁸):(2³)⁵​ = (2¹⁸+2²˙⁸) : 2³˙⁵ = (2^18 + 2^16) : 2^15 = 2^18 : 2^15 + 2^16 : 2^15 = 2^(18-15) + 2^(16-15) = 2³ + 2 = 8+2 = 10

Answer 2

Răspuns:

a) 3 la 0+ 0 la 3+ 2 la 3= 1+ 0+ 8=9

b) 3 la 5* 3 la 8: 3 la 11= 3 la 5+8-11=3 la 2=9

c) 36:(2 la 2 * 3)+72:(2*3 la 2)=36:12+72:18=3+4=7

d) (2 la 18+ 4 la 8):8 la 5=(2 la 18 + 2 la 16):2 la 15=2 la 18:2 la 15 = 2 la 18: 2 la 15= 2 la 3+ 2 la 1=8 = 2= 10

Explicație pas cu pas:

4 la 8= (2 la 2) la 2

8 la 5= (2 la 3) la 5

2 la 18: 2 la 15= 2 la 18-15= 2 la 3( la fel pentru urmatoarea)