Question

calculati a) 3^101:9^50 b) (3^57:9^25×3^10):3^15 c) 2×4×2^43-2^46+[9^74:3^43-(3^15)^6]^0

Answer 1

Răspuns

Explicație pas cu pas:

a)    3¹⁰¹ : 9⁵⁰ = 3¹⁰¹ : ( 3² ) ⁵⁰ = 3¹⁰¹ : 3¹⁰⁰ = 3 ⁽ ¹⁰¹ ⁻ ¹⁰⁰ ⁾ = 3¹ = 3

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b)   ( 3⁵⁷ : 9²⁵ x 3¹⁰ ) : 3¹⁵ =

= [ 3⁵⁷ : ( 3² ) ²⁵  x 3¹⁵ ] : 3¹⁵ =

= ( 3⁵⁷ : 3⁵⁰ x 3¹⁵ ) : 3¹⁵ =

= 3 ⁽ ⁵⁷ ⁻ ⁵⁰ ⁺ ¹⁵ ⁾  : 3¹⁵ =

= 3⁽²² ⁻ ¹⁵ ⁾ =

= 3⁷

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2 x 4 x 2⁴³ - 2⁴⁶ + [ 9⁷⁴ : 3⁴³ - ( 3¹⁵ )⁶ ] ⁰ =

= 2 ⁽ ¹ ⁺ ² ⁺ ⁴³ ⁾ - 2⁴⁶ + 1 =

= 2⁴⁶ - 2⁴⁶ + 1 =

= 1

Orice numar ridicat la puterea 0 este 1