Question

Calculati:
a) 3/11+15/33-6/11+3/44
b)1-23/44+17//11-31/33

Answer 1

poftim .............

Answer 2

$a) \frac{3}{11} + \frac{15}{33} - \frac{6}{11} + \frac{3}{44} = \\ \\ \frac{3}{11} + \frac{15}{33} = \frac{3 \times 3}{11 \times 3} + \frac{15}{33} = \frac{9}{33} + \frac{15}{33} = \frac{9 + 15}{33} = \frac{24}{33}^{(3} = \frac{8}{11} \\ \\ \frac{8}{11} - \frac{6}{11} = \frac{8 - 6}{11} = \frac{2}{11} \\ \\ \frac{2}{11} + \frac{3}{44} = \frac{2 \times 4}{11 \times 4} + \frac{3}{44} = \frac{8}{44} + \frac{3}{44} = \frac{8 + 3}{44} = { \frac{11}{44} }^{(11} = \frac{1}{4}$

$b)1 - \frac{23}{44} + \frac{17}{11} - \frac{31}{33} = \\ \\ 1 - \frac{23}{44} = \frac{1}{1} - \frac{23}{44} = \frac{1 \times 44}{1 \times 44} - \frac{23}{44} = \frac{44}{44} - \frac{23}{44} = \frac{44 - 23}{44} = \frac{21}{44} \\ \\ \frac{21}{44} + \frac{17}{11} = \frac{21}{44} + \frac{17 \times 4}{11 \times 4} = \frac{21}{44} + \frac{68}{44} = \frac{21 + 68}{44} = \frac{89}{44} \\ \\ \frac{89}{44} - \frac{31}{33} = \frac{89 \times 3}{44 \times 3} - \frac{31 \times 4}{33 \times 4} = \frac{267}{132} - \frac{124}{132} = \frac{267 - 124}{132} = { \frac{143}{132} }^{(11} = \frac{13}{12} = 1 \frac{1}{12}$