Matematică, întrebare adresată de boberschilacram, 9 ani în urmă

calculati
a)3+2*1/5=
b)5-3*1/4=
c)3/2+3/4*1/2=
d)0,25:0,5*1/4=
e)1/2+2*(0,25+3)=
f)3,25-3(1,7-3/2)=
g)5/2+3la a 2*0,25=
h)3/4-[2/5]la a2=
i)0,4+[1/3]la a 2*5=
j)0,75+0,08(3):1/6=
k)0,6+3/5:1,2+1/2*0,4=
va rog ajutati ma celui mai bun dau coroana ]raspunsuri finale sunt
a=3intregi2/5=3,4
b=4intregi1/4=4,25
c=1intreg7/8=1,875
d=1/8=0,125
e=7
f=2,65
g=?
h=4,75
i=0,59
j=1
k=1intreg1/4=1,25
l=37/10=1intreg7/10=1,2(3)
va rog multumesc

Răspunsuri la întrebare

Răspuns de renatemambouko
32
a)3+2*1/5=3+2/5=(15+2)/5=17/5= 3 intregi 2/5 = 3,4
b)5-3*1/4=5-3/4=(20-3)/4=17/4=4 intregi 1/4=4,25
c)3/2+3/4*1/2=3/2+3/8=(12+3)/8=15/8=1 intreg 7/8 =1,875
d)0,25:0,5*1/4=25/100:5/10 *1/4=1/4 * 2/1 *1/4=1/2*1/4=1/8=0,125
e)1/2+2*(0,25+3)=1/2+2*(25/100+3)=1/2+2*(1/4+3)=1/2+1/2+6=2/2+6=1+6=7
f)3,25-3(1,7-3/2)=325/100-3(17/10-3/2)=13/4-3(17-15)/10=13/4-6/10=
=13/4-3/5=(65-12)/20=53/202,65=
g)5/2+3la a 2*0,25=5/2+9*25/100=5/2+9/4=(10+9)/4=19/4=4 intregi 3/4=4,75
h)3/4-[2/5]la a2=3/4-4/25=(75-16)/100=59/100=0,59
i)0,4+[1/3]la a 2*5=4/10+1/9 *5 =2/5+5/9=(18+25)/45=43/45=0,9(5)
j)0,75+0,08(3):1/6=75/100+(83-8)/900 * 6= 3/4+75/150 =3/4+1/2=(3+2)/4=5/4= =1 intreg 1/4 = 1,25
k)0,6+3/5:1,2+1/2*0,4=6/10+3/5 :12/10+1/2*4/10=3/5+3/5*10/12+1/2*2/5= =3/5+1/2+2/10= (6+5+2)/10=13/10=1 intreg 3/10 =1,3


boberschilacram: l=?
boberschilacram: multumesc mult pe punctul l nu stiti?
boberschilacram: scz
renatemambouko: dar pct l nu l-ai scris
boberschilacram: da nu am gresit e bine asa multumesc
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