Question

calculați:
a) 3,7×(2, 59+2, 41) ;
b) 6,12×(4, 23-4, 03) ;
c) (12, 5+2, 5) ×(10-0, 9) ;
d) (6, 12-5, 93)
............×............
(78, 124+21,876)

ajutați-mā,vā rog! ​

Answer 1

Explicație pas cu pas:

a) 3,7 × (2,59+2,41)= 3,7×5= 18,5

b) 6,12×(4,23-4,03)= 6,12×0,2= 1,224

c) (12,5+2,5)×(10-0,9)= 15+9,1=24,1