Matematică, întrebare adresată de violetababalau, 9 ani în urmă

Calculati:
A) √3²+4²+√7²+15²+√5²+12²
B)(2√3)²-√6²+√(-5)²-(-2)³√(-12)²
C)√12•√3+√20•√5•√3•√6•√18+√2⁴•7²
D)√5{4+2•[(√7-√3)(√7+√3)-2]}
E)(√4+√9-√13)(5+√13)-√(-7)²
F)15√80:(3√5)+6√288:(-2√2-21√338:(-7√2)
G)(2-√3+√5)(2+√3-√5)-2√15
H)(√10-3)(√10+3)+(5√3-2)(√5-√3)(√5+√3)-(3-√5)²

Răspunsuri la întrebare

Răspuns de renatemambouko
1
A) √3²+4²+√7²+15²+√5²+12²=
=3+16+7+225+5+144=400
B)(2√3)²-√6²+√(-5)²-(-2)³√(-12)²=
=12-6+5+8•12=
=6+5+96=107
C)√12•√3+√20•√5•√3•√6•√18+√2⁴•7²=
=6+10•18+2²•7=
=186+28=214


D)√5{4+2•[(√7-√3)(√7+√3)-2]}=
=√5{4+2•[(7-3)-2]}=
=√5[4+2•(4-2)]=
=√5(4+4)=
=8√5
E)(√4+√9-√13)(5+√13)-√(-7)²=
=(2+3-√13)(5+√13)-7=
=(5-√13)(5+√13)-7=
=25-13-7=5

F)15√80:(3√5)+6√288:(-2√2)-21√338:(-7√2)=
=60√5:(3√5)+72√2:(-2√2)-273√2:(-7√2)=
=20-36+39=
=23

G)(2-√3+√5)(2+√3-√5)-2√15=
=4-2√3+2√5+2√3-3+√15-2√5+√15-5-2√15=
=1-5=-4

H)(√10-3)(√10+3)+(5√3-2)(√5-√3)(√5+√3)-(3-√5)² =
=(10-9)+(5√3-2)(5-3)-(9-6√5+5) =
=1+(5√3-2)×2-14+6√5 =
=1+10√3-4-14+6√5 =
=10√3+6√5-17


















violetababalau: Multumesc mult
renatemambouko: ok
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