Question

Calculati:
a .) 3²•5²-3²•2³=
b.)10•{18²:324+2•[(2²•3)15:(2^29•3^15)+2006^0]}

Answer 1

10*{324:324+2*[($2^{30}$$* 3^{15}$ : ($2^{29} * 3^{15}$)+1]}= 10* [1+2*(2+1)]=10*(1+6)= 10*7=70