Question

Calculați:
a) (4+2 la puterea 4:2 la puterea 2):2 la puterea 2=
b) (49+7 la puterea 57:7 la puterea 55):7+3 la puterea 0=
c) (36+6 la puterea 69:6 la puterea 67+4×6 la puterea 2=
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Answer 1

$a)(4 + 2 ^{2} ) \div 2 {}^{2} = 8 \div 4 = 2 \\ b)(49 + 7 {}^{2} ) \div 7 + 0 = 7 {}^{4} \div 7 = 7 {}^{3} = 34 \\ c)36 + 6 {}^{2} + 4 \times 6 {}^{2} = 36 + 36 + 4 \times 36 = 216$

Sper ca te-am ajutat!