Question

calculati
A {4 radical 2+ 4[3 radical 3+3(3 radical 2-radical 3)]}:10-radical 2=
B 3 radical 5- 7{radical 2 +{20 radical 5 - 2(radical 5 - 9 radical 2):18}=
C radical 63[ 7 radical 27- 3(7 radical 3 + radical 28] + 16=
D 30 radical 180 + 4 radical 5{ 18 radical 2- 3 radical 5{ 2 radical 40 - 3( 2 radical 40 - radical 5)]}=

Answer 1

A) {4√2+4[3√3+3(3√2-√3)]}:10-√2=[4√2+4(3√3+9√2-3√3)]:10-√2=(4√2+12√3+36√2-12√3):10-√2=40√2•1\10-√2=4√2-√2=3√2 C) √63[7√27-3(7√3+√28)]+16=3√7(3√3-21√3-6√7)+16=9√21-63√21-18√49+16=-54√21-126+16=-54√21+110 D) 30√180+4√5{18√2-3√5[2√40-3(2√40-√5)]}=180√5+4√5[18√2-3√5(2√10-12√10-3√5)]=180√5+4√5(18√2-6√50+36√50+9√25)=180√5+4√5(330√2+35)=180√5+1320√10+140√5=320√5+1320√10