Question

Calculati:
A) √432×(√726-√486+√294-√600)+120√2
B) √162×(√75-√147+√48-√300)+ 12√24

Answer 1

Răspuns:

Explicație pas cu pas:

Answer 2

Răspuns:

$A=84\sqrt{2}$

$B=-48\sqrt{6}$

Explicație pas cu pas:

$\sqrt{432} *(\sqrt{726} -\sqrt{486} +\sqrt{294} -\sqrt{600} )+120\sqrt{2} =$

$12\sqrt{3} *(11\sqrt{6} -9\sqrt{6} +7\sqrt{6} -10\sqrt{6} )+120\sqrt{2} =$

$12\sqrt{3} *[(11-9+7-10)\sqrt{6} ]+120\sqrt{2} =$

$12\sqrt{3} *(-\sqrt{6} )+120\sqrt{2} =$

$-12\sqrt{18} +120\sqrt{2} =$

$-12*3\sqrt{2}+120\sqrt{2} =$

$-36\sqrt{2} +120\sqrt{2} =$

$84\sqrt{2}$

$\sqrt{162} *(\sqrt{75} -\sqrt{147} +\sqrt{48} -\sqrt{300} )+12\sqrt{24} =$

$9\sqrt{2} *(5\sqrt{3} -7\sqrt{3} +4\sqrt{3} -10\sqrt{3} )+12\sqrt{24} =$

$9\sqrt{2} *[(5-7+4-10)\sqrt{3} ]+12*2\sqrt{6} =$

$9\sqrt{2} *(-8\sqrt{3} )+24\sqrt{6} =$

$-72\sqrt{6} +24\sqrt{6} =$

$-48\sqrt{6}$