Question

calculați
a) (5^0+5^1+5^2)^4:31^4+31^0
b) (16+2^13:2^9):2^5
c)(7^0+7^1+7^2)^5:57^4+57^0
d) (4+2^200:2^198):2^3
varooooooog ajutați mă este urgent​

Answer 1

Răspuns:

d) ( 4 + 2²⁰⁰ : 2¹⁹⁸ ) : 2³ = 1

( 4 + 2² ) : 2³ =

( 4 + 4 ) : 8 =

8 : 8 = 1

b) ( 16 + 2¹³ : 2⁹ ) : 2⁵ = 1

( 16 + 2⁴ ) : 32 =

( 16 + 16 ) : 32 =

32 : 32 = 1

c) ( 7⁰ + 7¹ + 7² ) ⁵ : 57⁴ + 57 ⁰ = 58

( 1 + 7 + 49) ⁵ : 57⁴ + 1 =

57⁵ : 57⁴ + 1 =

57¹ + 1 =

57 + 1 = 58

a) ( 5⁰ + 5¹ + 5² )⁴ : 31⁴ + 31⁰ = 2

( 1 + 5 + 25 ) ⁴ : 31⁴ + 1 =

31⁴ : 31⁴ + 1 =

31⁰ + 1 =

1 + 1 = 2