Question

calculati:a.(5\11)^6x(22\10)^6 b.(5 2\5)^4 x (5\9)^4 c.(39\54)^8 x (27\26)^8 ofer 32 de puncte va roog mult

Answer 1

Răspuns:

a) $1$

b) $81$

c) $(\frac{3}{4})^{8}$

Explicație pas cu pas:

a) $(\frac{5}{11})^{6} *(\frac{22}{10})^{6} = (\frac{5}{11}*\frac{22}{10})^{6} = (\frac{5*22}{11*10})^{6} = (\frac{110}{110})^{6} = 1^{6} = 1$

b) $(5\frac{2}{5})^{4} * (\frac{5}{9})^{4} = (\frac{5*5+2}{5})^{4} * (\frac{5}{9})^{4} = (\frac{27}{5})^{4}*(\frac{5}{9})^{4} = (\frac{27*5}{5*9})^{4} = (\frac{135}{45})^{4} = 3^{4} = 81$

c) $(\frac{39}{54})^{8}*(\frac{27}{26})^{8} = (\frac{13}{18})^{8}*(\frac{27}{26})^{8} = (\frac{13*27}{18*26})^{8} = (\frac{13*3*9}{2*9*2*13})^{8} = (\frac{3}{4})^{8}$