Question

Calculati:a)(5^2-2^5):3-1^2019 b)(3^2×2^6-2^5×6):12-2^5 c) (7^4-7^3):(7^2-7)-2^3×5

Answer 1

$a) (5^{2}-2^{5}):3-1^{2019}= \\ (25-32):3-1= \\ -7:3-1= \frac{-7-3}{3}= -\frac{10}{3} \\ \\ b)(3^{2}*2^{6}-2^{5}*6):12-2^{5}= \\ (9*64-32*6):12-32= \\ (576-192):12-32= \\ 384:12-32=0 \\ \\ c)(7^{4}-7^{3}):(7^{2}-7)-2^{3}*5= \\ (2401-343):42-8*5= \\ 2058:42-40=49-40=9$

/robèrtinni