Question

Calculati:
a) -7(2)+18,(5) 
b)-3,2(1)+5,4(3) 
c)5 intregi si 3/7+ (-4,5)+(-7 intregi si 1/2)
d)(-1/3)+ (-2/+9)+(-5/-27)=(10/-81) ⇒ minusul este doar in fata lui 2
e)-7 intregi si 3/8 + 2 intregi si 3/4 + 5,(3)   
g)2 intregi si 1/5 + (-1 intregi si 3/4)+9,15+(-3) 
h)-3,2(5)+6,4(32)+(-7/9) 
P.s:Nu imi da ca la sfarsit si de-aia am pus intrebarea.

Answer 1

a)-7(2)+18,(5)=11,(3)

b)-3,2(1)+5,4(3)=2,2(2)

c)5 intregi 3/7 + (-4/5)+ (-7 intregi 1/2)= 

5 intregi 3/7= 38/7
-7 1/2= -15/2

38/7 -4/5 -15/2   aducem la acelasi numitor

(380-56-525)/70=  (380-581)/70=  -201/70= -2 intregi 61/70

d)(-1/3)+ (-2/9)+ (-5/-27)+(10/-81)= -1/3 -2/9 +5/27 -10/81  aducem la acelasi numitor

(-27-18+15-10)/81=  (-55+15)/81= -40/81

e)-7 intregi 3/8 + 2 intregi 3/4+5,(3)=

-7intregi 3/8= -59/8
2 intregi 3/4= 11/4
5,(3)=5 intregi 3/9= 5 intregi  1/3=  16/3

-59/8 +11/4 +16/3  aducem la acelasi numitor=

(-177+66+128)/24=  (-177+194)/24=  -17/194

f)2 intregi 1/5 +(-1 intreg 3/4) +9,15 +(-3)= 2 intregi 1/5 -1 intreg 3/4 +9,15 -3

2 intregi 1/5= 11/5
-1 intreg 3/4=-7/4
9,15=9 intregi 15/100= 9 intregi 3/20= 183/20

11/5 -7/4 +183/20 -3  aducem la acelasi numitor

(44-35+183-60)/20= (227-95)/20=  -132/20= -6 intregi 12/20

g)-3,2(5)+6,4(32)+(-7/9)=

-3,2(5)=-3 intregi  (25-2)/90=-3 intregi 23/90= -293/90
6,4(32)=6 intregi  (432-4)/990= 6 intregi 428/990= 6368/990

-293/90 +6368/990 -7/9   aducem la acelasi numitor
(-3223+6368-770)/990=  (-3993+6368)/990=  2375/990 =2 intregi 395/990
= 2 intregi 79/198