Question

Calculati:
a) 7:(5/2 - 2/5) + 11/30 : 1 intreg si 2/3 + (-1) la puterea 2005; HELP!

Answer 1

1intreg2/3=(1x3+2)/3=5/3
=7:[(5x5-2x5)/10]+11/30:5/3-1
=7:[(25-10)/10]+11/30x3/5-1   simplificam in a ii fractie cu 3
=7:15/10+11/10x1/5-1
=7:3/2+11/50-1
=7x2/3+11/50-1
=14/3+11/50-1     aducem la acelasi numitor
=(14x50+11x3-150)/150=
=(700+33-150)/150
=583/150=3,88(6)