Question

Calculați:
a) 9 la 5-(3 la 5) totul la 2+8 la 4-(2 la 4) totul la 3
b) 2 la 7:4 la 3+3 la 3•27:3 la 5+(3 la 1•2 la 4-4 la 2):2 la 3

Vă rog să mă ajutați!

Answer 1

Răspuns:

• a) 0
• b) 24

a) 0b) 24Explicație pas cu pas:

Sautare!

$\bf \: a) \:{9}^{5} -({3}^{5})^{2}+{8}^{4} - ( {2}^{4})^{3} =$

$\bf ({ {3}^{2}})^{5} -{3}^{5 \cdot2}+({ {2}^{3} })^{4} - {2}^{4 \cdot3} =$

$\bf {3}^{2 \cdot5} -{3}^{10}+{2}^{3 \cdot4} - {2}^{12} =$

$\bf {3}^{10}-{3}^{10}+{2}^{12}-{2}^{12} =$

$\bf 0+0=$

$\boxed{\bf 0}$

$\bf b) \: {2}^{7} :{4}^{3} + {3}^{3} \cdot27:{3}^{5}+({3}^{1} \cdot 2^{4}-{4}^{2}):2 + 3 =$

$\bf {2}^{7}:({2}^{2})^{3} + {3}^{3} \cdot {3}^{3}:{3}^{5}+(3 \cdot 16 -16): 2 + 3 =$

$\bf {2}^{7} : {2}^{2 \cdot3} + {3}^{3 + 3}: {3}^{5}+(48 -16): 2 + 3 =$

$\bf {2}^{7} : {2}^{6} + {3}^{6}: {3}^{5}+32:2 + 3 =$

$\bf {2}^{7 - 6} + {3}^{6 - 5}+16+ 3 =$

$\bf {2}^{1} + {3}^{1}+16+ 3 =$

$\bf 2 + 3+16+ 3 =$

$\boxed{\bf 24}$

==pav38==