Question

Calculați:
a) a= [a⁵•a⁷+(a¹)²⁰]⁰:[(a²)⁴:(a⁴)²]
b) b= [(2³)⁵+25³-7³⁵:7²⁰]:(2¹⁵-7¹⁵+5⁶)•3³⁶
c) c= [2+2²•2²²+2²⁰⁰:2¹²⁰+(3³)¹⁰]:[1+2²⁴+2⁸⁰+2²⁰¹³+3³⁰]-2+(5⁷)

VĂ ROOG!!​

Answer 1

a= [a⁵•a⁷+(a¹)²⁰]⁰:[(a²)⁴:(a⁴)²] =
( prima paranteză pătrată= 1, fiindcă orice număr la puterea 0= 1)
a= 1:[a^8:a^8]=
a= 1:1
a= 1


B) [(2³)⁵+25³-7³⁵:7²⁰]:[2¹⁵-7¹⁵+5⁶]•3³⁶=
[2³•5+(5²)³-7³⁵-20]:[2¹⁵+5⁶-7¹⁵]•3³⁶=
[2¹⁵+5⁶-7¹⁵]:[2¹⁵+5⁶-7¹⁵] •3³⁶=
1•3³⁶= 3³⁶

C) [2+2²•2²²+2²⁰⁰:2¹²⁰+(3³)¹⁰]:[1+2²⁴+2⁸⁰+2²⁰¹³+3³⁰]-2+(5⁷)³=
(2+2²⁴+2⁸⁰+3³⁰):(1+2²⁴2⁸⁰+2²⁰¹³+3³⁰)-2+5²¹ (2+2²⁴+2⁸⁰+3³⁰):(1+2²⁴2⁸⁰+2²⁰¹³+3³⁰)-2+5²¹