Question

calculati (a+b-1) : c stiind ca: 3×a-5=55 ,100+2×b=164 ,(c-1)×7+1=15

Answer 1

3×a-5=55
3×a=55+5
3×a=60
a=60÷3
a=20

100+2×b=164
2×b=164-100
2×b=64
b=64÷2
b=32

(c-1)×7+1=15
c-1=15-1÷7
c-1=14÷7
c-1=2
c=2+1
c=3

(a+b-1)÷c=(20+32-1)÷3=51÷3=17

Raspuns:17

Answer 2

3×a-5=55 l +5          3×a=60  l :3       a=20

100+2×b=164  l -100        2×b=64  l :2         b=32

(c-1)×7+1=15  l-1    (c-1)×7=14  l:7     c-1=2  l+1    c=3

(a+b-1):c      Inlocum valorile aflate:

(20+32-1):3=51:3=17