Question

Calculati a·b(b+c) si a·b - a·c , unde:
a=4√33:√11+14√30:(2√10)-3·2√3+9√39:√13
b=3√2·3√3+4√6·(-2)-4√2·√3+√2·√3
urgent,mersi

Answer 1

$a = 4 \sqrt{3}+7\sqrt{3}-6\sqrt{3}+9\sqrt{3} \\ a = 14\sqrt{3} \\ \\ b=9\sqrt{6}-8\sqrt{6}-4\sqrt{6}+\sqrt{6} \\ b=-2\sqrt{6} \\ \\ c=3\sqrt{6}-\sqrt{15}+\sqrt{6}-2\sqrt{10}+\sqrt{15}+2\sqrt{10} \\ c=4\sqrt{6} \\ \\ a*b*(b+c)=14\sqrt{3}*(-2\sqrt{6})*(-2\sqrt{6}+4\sqrt{6})=-336\sqrt{3} \\ a*(b-c)=14\sqrt{3}*(-2\sqrt{6}-4\sqrt{6})=-252\sqrt{2}$

/robèrtinni

Answer 2

a=4√33:√11+14√30:(2√10)-3·2√3+9√39:√13=
=4√3+7√3-6√3+9√3=
=14√3

b=3√2·3√3+4√6·(-2)-4√2·√3+√2·√3=
=9√6-8√6-4√6+√6=
=-2√6

c=√3·(3√2-√5)+√2·(√3-2√5)+√5·(√3+2√2)=
=3√6-√15+√6-2√10+√15+2√10=
=4√6

a·b(b+c) =14√3×(-2√6)(-2√6+4√6)=-14√3×24=-56√108=-336√3
 a·b - a·c =a(b-c)=14√3×(-2√6-4√6)=-14√3×6√6=-252√2