Question

Calculati:
a)cantitatea de Al(OH)2 care contine 6g H
b)cantitatea de Al care se afla in 780g Al(OH)3

Answer 1

6g H2               MAl(OH)3=27+3.16+3=78
? g H2          78g (AlOH)3----------3 gH2
                        Xg---------------------6gH2
                         X=78.6:3=156 g Al(OH)3


780g Al(OH)3          MAl(OH)3=78
?gAl                       78g Al(OH)3-------27 g Al
                              780g Al(OH)30--------       x g Al
                               x=780.27:78=270 g Al