Question

Calculați:
a)
${3}^{101} \div {9}^{50}$
b)
$( {3}^{57} \div {9}^{25} \times {3}^{10} ) \div {3}^{15}$
c)
$2 \times 4 \times {2}^{43} - {2}^{46} + ( {9}^{74} \div {3}^{43} - ( {3}^{15} ) {}^{6} ) {}^{0}$
(aici nu am scris bine,uitați-vă în poza)​

Answer 1

a)

$3^{101}: 9^{50}= 3^{101}: 3^{2*50}= 3^{101}: 3^{100}= 3^{1} =3$

b)

$(3^{57} :9^{25}* 3^{10} ):3^{15}= (3^{57} :3^{2*25}* 3^{10} ):3^{15}= (3^{57} :3^{50}* 3^{10} ):3^{15}= (3^{7} * 3^{10} ):3^{15}= 3^{17} :3^{15}= 3^{2} =9$

c)

$2*4*2^{43} -2^{46} +(9^{74} :3^{43}-(3^{15}) ^{6} )^{0} =2*2^{2} *2^{43} -2^{46} +1 =\\2^{46} -2^{46} +1=0+1=1$