Question

calculați:
a) $(-9)^{73}$÷$3^{144} - 16^{12}$÷$4^{23}$

b)

Answer 1

( - 9 ) ⁷³ = numar negativ la putere impara  =  -  9⁷³  = - ( 3² ) ⁷³ = - 3 ¹⁴⁶
- 3¹⁴⁶ : 3¹⁴⁴ - ( 4² )¹² : 4²³ = - 3 ¹⁴⁶ ⁻ ¹⁴⁴   - 4 ²⁴ : 4²³ = - 3² - 4 ²⁴ ⁻²³ = 
= - 9 - 4¹ = - 9 - 4 = - 13

Answer 2

$a).(-9)^7^3:3^1^4^4-16^1^2:4^2^3=-(3^2)^7^3:3^1^4^4-(4^2)^1^2:4^2^3= \\ =-3^1^4^6:3^1^4^4-4^2^4:4^2^3=-3^1^4^6^-^1^4^4-4^2^4^-^2^3= \\ =-3^2-4^1-9-4=-13 \\ b).[(-4)^2-(3)^7^7:(-3)^7^5]:7=[(-4)^2-3^7^7^-^7^5]:7= \\ =(16-3^2):7=(16-9):7=7:7=1$