Question

Calculați:
a)$\frac{2-3x}{ x^{2} -x}+ \frac{2}{x-1}+ \frac{5}{3x}=$
b)$\frac{3x+1}{ 2x^{2}-6x }- \frac{x+2}{3x-9}+ \frac{2x-1}{6x} =$
Rezolvare completa va rog....Mulțumesc!

Answer 1

a) (2-3x)/(x²-x)+2/(x-1)+5/3x=
=(2-3x)/x(x-1)+2/(x-1)+5/3x=
=(6-9x+6x+5x-5)/3x(x-1)=
=(1+2x)/3x(x-1)
b) (3x+1)/(2x²-6x)-(x+2)/(3x-9)+(2x-1)/6x=
= (3x+1)/2x(x-3)-(x+2)/3(x-3)+(2x-1)/6x=
= (9x+3-2x²-4x+2x²-x-6x+3)/6x(x-3)=
= (9x+6-11x)/6x(x-3)=
= (-2x+6)/6x(x-3)=
= -2(x-3)/6x(x-3)=
= -1/3x