Question

Calculați:
a) :
$\frac{a}{19} + \frac{11a}{19} + \frac{7a}{19}$
b) :
$\frac{3a}{23} + \frac{17a}{23} + \frac{26a}{23}$
c) :
$\frac{11x}{49} + \frac{13x}{49} + \frac{25x}{49}$
d) :
$\frac{15b}{7} - \frac{3b}{7} - \frac{5b}{7}$
e) :
$\frac{21y}{11} - \frac{7y}{11} - \frac{3y}{11}$
f) :
$\frac{29c}{47} - \frac{21c}{47} - \frac{8c}{47}$
VA ROG SA IMI EXPLICATI PAS CU PAS!!! Tema pt clasa a V-a​

Answer 1

Explicație pas cu pas:

$a) \: \frac{a}{19} + \frac{11a}{19} + \frac{7a}{19} =\frac{a+11a+7a}{19} = \frac{\not19a}{\not19} {}^{(19} =\red{a} \\ b) \: \frac{3a}{23} + \frac{17a}{23} + \frac{26a}{23}=\frac{3a+17a+26a}{23} = \frac{\not46a}{\not23} {}^{(23} =\red{2a} \\ c) \:\frac{11x}{49} + \frac{13x}{49} + \frac{25x}{49} =\frac{11x+13x+25x}{49}= \frac{\not49x}{49} {}^{(\not49} = \red{x}$

$d) \: \frac{15b}{7} - \frac{3b}{7} - \frac{5b}{7} =\frac{15b-3b-5b}{7}= \frac{\not7b}{\not7} {}^{(7} =\red{b} \\ e) \: \frac{21y}{11} - \frac{7y}{11} - \frac{3y}{11} =\frac{21y-7y-3y}{11} = \frac{\not11y}{\not11} {}^{(11} =\red{ y} \\ f) \: \frac{29c}{47} - \frac{21c}{47} - \frac{8c}{47} =\frac{29c-21c-8c}{47}= \frac{0}{47}=\red{0}$