Question

calculați:
a)
$\sqrt{48} + \sqrt{75} + \sqrt{27} - \sqrt{300 = }$
varog urgenttt ajutațimă ​

Answer 1

$\sqrt{48} + \sqrt{75} + \sqrt{27} - \sqrt{300 } = \\ 4 \sqrt{3} + 5 \sqrt{3} + 3 \sqrt{3} - 10 \sqrt{3} = \\ 9 \sqrt{3} + 3 \sqrt{3} - 10 \sqrt{3} = \\ 12 \sqrt{3} - 10 \sqrt{3} = \\ = 2 \sqrt{3}$

Answer 2

$\it \sqrt{48}+\sqrt{75}+\sqrt{27}-\sqrt{300}=\sqrt3(\sqrt{16}+\sqrt{25}+\sqrt{9}-\sqrt{100})=\\ \\ =\sqrt3(4+5+3-10)=2\sqrt{3}$