Question

Calculați (ab) la puterea 2
a) a=-3; b=-1;
b) a=-4; b=+2;
c) a=+9; b=-1;
d) a=-3; b=-2

Answer 1

$a)a = - 3$

$b = - 1$

${(ab)}^{2} = { [ - 3 \times ( - 1)]} ^{2} = {3}^{2} = 9$

$b)a = - 4$

$b = + 2$

${(ab)}^{2} = {[ - 4 \times ( + 2)]} ^{2} = {( - 8)}^{2} = 64$

$c)a = + 9$

$b = - 1$

${(ab)}^{2} ={ [9 \times ( - 1)]} ^{2} = {( - 9)}^{2} = 81$

$d)a = - 3$

$b = - 2$

${(ab)}^{2} = {[ - 3 \times ( - 2)]} ^{2} = {6}^{2} = 36$

Answer 2

Calculați (ab) la puterea 2

a) a=-3; b=-1; (a×b)²= [( - 3)×( - 1)]² = 3² = 9

b) a=-4; b=+2; (a×b)²= [( - 4)×(2)]² = (- 8)² = 64

c) a=+9; b=-1; (a×b)²= [( 9)×(-1)]² = (- 9)² = 81

d) a=-3; b=-2 (a×b)²= [( -3)×(-2)]² = (+6)² = 36